Help for 3rd Grade Math

Introduction to help for 3rd grade math:
In this article  we are going to help for 3rd grade  math student ,those 3rd grade students need help in basic operation of math like place value, compare numbers, addition, subtraction, multiplication, division, conversion of units like kilometer, meter, centimeter, millimeter, how to draw the graph  and also they need help in geometry.

I like to share this Tangent Line Equation with you all through my article.

Example - help for 3rd grade math


Which symbols are used for compare the numbers?
Solution:
Generally in comparison of number we use the symbol as < (less than),> (greater than), <=(less than or equal to),>= (greater than or equal to)
suppose take the  number as 24 and 12 ,here the number 24 is less than the 12 ,so it will be used in the form of 24>12

Example - help for 3rd grade math
8 hundreds+4 tens. How those expression will be written in number format
Solution:
Here 8 hundreds will be written as 800 then 4 tens will be written as 40 after that we have to note one thing in-between the plus sign will be there so after converging in the number format we have to add 800+40=840
So the answer is 840.

Example - help for 3rd grade math
What is the value of the underlined digit 789?
Solution:
Here place value of 7 will be written as 70, place value of 8 will be written as 80 and place value of 9 will be written as 9, so the value of the underlined digit is 80.

Understanding hard math word problems is always challenging for me but thanks to all math help websites to help me out.

Example - help for 3rd grade math


Solve 32-11
Solution:
Here we are doing the operation as subtraction it means removing some of the objects from the group here 11 will be removed from 22
First we subtract ones digit place 2-1=1 then do the operation is tens digit place 3-1=2
Combine these two digits we get the answer 21, it will be shown below.

Math Notes for Grade 8

Math notes for grade 8:

In this article we are going to discuss about find the math notes for grade 8.Math notes for grade 8 are easy to understand and solve. Math notes for grade 8 problems involve basic addition, subtraction, multiplication and division problems. Those arithmetic problems involve biggest numbers. The following topics are studied in the 8 grade,

Numbers
Measures
Algebra
Geometry
Handling data.
The math notes for grade 8 solving problems are given below.

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Example problems of math notes for grade 8:


Example 1:

Sum of 3 consecutive odd numbers is 51. Find the numbers.

Solution:

Framing the equation:

Let the first odd numbers be x.

Then the second and third odd numbers are (x+2) and (x+4)

There sum is 51.

x+(x+2)+(x+4) = 51

x+x+2+x+4 = 51

3x + 6 = 51(adding the like terms)

3x+6 = 51 is the required equation.

Solving the equation:

3x+6 = 51

3x = 51 – 6 (by rule 1)

= 45

x = 45 * `1/3 ` (by rule 3)

x = 15

The consecutive odd numbers are x, (x=2), (x=4)

15, (15+2) and (15+4)

The required numbers are 15, 17 and 19.

Example 2:

If office managers fixed in the pay scale 3200 – 85 – 4900, when will he reach his maximum?

Solution:

Pay scale: 3200 – 85 – 4900

Starting salary = $ 3200= a, Annual increment = $85 = d,

Maximum salary = $4900 = tn

tn = a + (n – 1)d = 4900 = 3200+(n-1) 85

n – 1 = 1700/85 = 20

n =20+1 = 21

The manager will reach his maximum in his 21st year of service.Having problem with math problems for 3rd grade keep reading my upcoming posts, i will try to help you.


Example 3:


The base and height of a right triangular ground are 60 m and 45 m. Find the cost of leveling the ground at Rs 150 per are ( 1 are = 100 sq.m)

Solution:

Given base b = 60m; height, h = 45m

Cost of leveling 1 are = Rs.150

Area of the triangular, A = `1/2` * 60 * 45

= 1350m2

100m2 = 1are

1350m2 = `1350/100` = 13.5are

Cost of leveling 1 are = Rs.150

Cost of leveling 13.5 Ares =Rs. 13.5 * 150 = Rs. 2025

Cost of leveling the right triangular ground = Rs. 2025

Example 4:

Find the circumference of a circle whose radius is 7cm.

Solution:

Radius r = 7cm

Circumference, C = 2`pi` r

= 2 * 22/7 * 7

= 44

Circumference of the circle = 44cm.

Example 5:

Solve 6x + 12 = 4x – 2

Solution:

Given expression 6x + 12 = 4x – 2

Subtract 12 on both sides of the equation

6x +12 – 12 = 4x – 2 -12

6x = 4x -14

Subtract 4x on both sides of the equation

6x – 4x = 4x – 4x -14

2x = -14

Divide 2 on both sides of the equation

`(2x)/2` =` -14/2`

x = -7

Solution is x = -7

Writing Equation Solver

Introduction to writing equation solver:

A linear equation solver is an arithmetical equation in which every word is either a stable or the multiplication of a stable and (the first power of) a distinct variable.

Linear equations solver can have single or many variables. Linear equations take place with great regularity in practical arithmetic. whereas they happen fairly logically when replica many phenomenon, they are mainly helpful because a lot of non-linear equations can be summary to linear equations by imagining that extent of interest vary to just a small extent from some "conditions" state

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Different types of linear equation solver:


They are three different types for writing linear equation solver:

Writing linear equation solver type: 1

Solve the given linear equation:  x + 7 = 5

Solution:

x + 7 = 5

x + 7 – 7 = 5 – 7          (Subtract 7 on both sides)

x = -2

So, the answer is x = -2

Writing linear equation solver type: 2

Solve the given linear equation: 3x – 8 = 7

Solution:

3x – 8 = 7

3x – 8 + 8 = 7 + 8       (Add 8 on both sides)

3x = 15

3x / 3 = 15 / 3              (Divide 3 on both sides)

x = 3.

So, the answer is x = 3.

Writing linear equation solver type: 3

Solve the given linear equation: 15x + 3 = 10x + 13

Solution:

15x + 3 = 10x + 13

15x + 3 - 3 = 10x + 13 – 3      (Subtract 3 on both sides)

15x = 10x + 10

15x – 10x = 10x – 10x + 10    (subtract by 10x on both sides)

5x = 10

5x / 5 = 10/ 5               (Divide 5 on both sides)

x = 2.

therefore, the answer is x = 2.

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Writing Linear equation in two variables:


A general structure of writing linear equation in the two variables x and y is

Y = mx + b.

Where m and b are select constants. The sources of the first name “linear” arrive from the information that the place of explanation of such an equation appearance a straight line in the plane. In this fastidious equation, the invariable m concludes the slope or gradient of that line, and the constant term b conclude the point at which the line traverse the y-axis, or else known as the y-intercept.

Algebra Solver Program

Introduction to algebra solver program:
Algebra solver program is a program which solves algebra problems with detailed solution in the stepwise manner. Solver program solves algebra problems. Algebra is the main branch in mathematics which deals the process of determining the unknown variable values . In algebra program the numbers are considered as constants. The following program shows the solved algebra problems.

Problems in algebra include simplifying expressions, finding the value of unknown variable, solve one step linear equations , functions , word problems of day to day life and so on. Algebra deals with the solutions of the problems in a structured , simple step by step procedure. Each step is small and the solution is thus obtained by a set of such steps.Here is a sample of the solver program that solves linear inequalities:

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Examples solved using the solver program of Algebra :


Ex 1:Solve the expression using algebra solver.

6(x -3) + 5y - 2(x -y -2) + 1

Sol:Step 1:Given the algebraic expression

6(x -3) + 5y - 2(x -y -2) + 1

Step 2:Multiplying the integer with above terms

= 6x - 18 + 5y -2x + 2y + 4 + 1

Step 3: Grouping the above terms

= 4x + 7y – 13 is the solution.

Ex 2:Solve the expression using algebra solver.

5(-2y - 2) - (-2y - 4) = -4(4y + 4) + 15

Sol:

Step 1:Given equation is

5(-2y - 2) - (-2y - 4) = -4(4y + 4) + 15

Step 2:Multiplying the integer with above terms
-10y - 10 + 2y + 4 = -16y - 16 +15

Step 3:Grouping the above terms

-8y - 6 = -16y - 1

Step 4:Add 8y and 1  on both sides, the above equation becomes

-5 =-8y

Y= `5/8`  is the solution

Ex 3:Solve the expression using algebra solver.

-2(y - 3) - 6y - 1 = 8(y +2) - 2y

Sol:

Step 1:Given
-2(y - 3) - 6y - 1 = 8(y + 2) - 2y

Step 2:Multiplying the factors
-2y + 6 - 6y - 1 = 8y + 16 - 2y

Step 3:Grouping the above terms
-8y + 5 = 6y + 16

Step 4:Subtract 6y + 5 on both sides
-8y + 5 – 6y -5 = 6y +16 -6y-5

Step 5:Grouping the above terms
-14y = 11

Y = -`11/14` is the solution.

Understanding algebra 2 help free is always challenging for me but thanks to all math help websites to help me out.

Practicing to solve algebra problems using the solver program:


1) Solve the expression using algebra solver.

6(-8y - 3) - (-5y - 5) = -8(2y + 4) + 9

Ans: y = `10/9` is the solution.

2) Solve the expression using algebra solver.

5(x -8) + 11y - 5(x -y +6) + 4

Ans: 16y – 66 is the solution.

Math Multi Steps Equations

Introduction to math multi steps equations:

An equation is a mathematical statement that asserts the equality of two expressions. Equations consist of the expressions that to be equal on opposite sides of an equal sign. (Source: Wikipedia).

The following rules are used to simplify the equation and the equation does not change.

1) Add or subtract any variable or number to the both sides of the equation

2) Multiply or divide any variable or number to the both sides of the equation.

3) Distributive law also used to eliminate the parentheses in the given equation. Distributive law is a(b + c) = a b + a c.

More than two steps are used to solve the equation is called as multistep equation. Now, we are going to see some of the problems on math multistep equations.

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Problems on math multistep equations:


Example problem 1:

Solve for the variable x: -6 = -4 (9 x + 6)

Solution:

-6 = -4 (9 x + 6)

Use the distributive law, to eliminate the parentheses

-6 = -4 (9 x) - 4 (6)

-6 = -36 x – 24

Add 24 on both sides of the equation

-6 + 24 = -36 x – 24 + 24

18 = - 36 x

Divide by -36 on both sides of the equation

(18 / -36) = -36 x / -36

-1 / 2 = x

So, the answer is x = -1 / 2.

Example problem 2:

Solve for the variable m: m + 10 = -5m + 34

Solution:

m + 10 = -5m + 34

Subtract 10 on both sides of the equation

m + 10 – 10 = -5m + 34 – 10

m = -5m + 24

Add 5m on both sides of the equation

m + 5m = -5m + 5m + 24

6m = 24

Divide by 6 on both sides of the equation

6m / 6 = 24 / 6

m = 4

So, the answer is m = 4.


Few more math multi step equations problems:


Example problem 3:

Solve for the variable x: 7(4t -3) – 1 = 13 + 21t

Solution:

7(4t -3) – 1 = 13 + 21t

To eliminate the parentheses, use the distributive law a (b + c) = a b + a c.

28t – 21 – 1 = 13 + 21t

28t – 22 = 13 + 21t

Add 22 on both sides of the equation

28t – 22 + 22 = 13 + 21t + 22

28t = 21t + 35

Subtract 21t on both sides of the equation

28t – 21t = 21t + 35 – 21t

7t = 35

Divide by 7 on both sides of the equation

7t / 7 = 35 / 7

t = 5

So, the answer is t = 5.

Example problem 4:

Solve the multi step equation for x: - (17 + x) – 6(-2 – x) = 35

Solution:

- (17 + x) – 6(-2 – x) = 35

To eliminate the parentheses, use the distributive law a(b + c) = a b + a c.

-17 – x + 12 + 6x = 35

-1x + 6x – 17 + 12 = 35

5x - 5 =35

Add 5 on both sides of the equation

5x - 5 =35

5x – 5 + 5 = 35 + 5

5x = 40

Divide by 5 on both sides of the equation

5x / 5 = 40 / 5

x = 8

So, the solution is x = 8.

I have recently faced lot of problem while learning Solving Absolute Value Equations, But thank to online resources of math which helped me to learn myself easily on net.

Practice problems on multistep equations:


1)    Solve for the variable t: -1t + 25 = t + 45

(Answer: t = -10)

2)    Solve for the variable y: 3(y + 1) = 7 + y - 13

(Answer: y = -4.5)

Definition of Base in Math

Introduction to definition of base in math:

In arithmetic, the radix or base refers the number b in an expression of form bn. The number n is called the exponent and the expression is known formally as exponentiation of b by n or the exponential of n with base b. It is more commonly expressed as "the nth power of b", "b to the nth power". (Source: Wikipedia).

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Examples for definition of base in math:


Example 1 for definition of base in math:

Find the base 2 for base 10 of 28.

Solution:

The given base 2 number is (28)10.

We have to convert the base 10 number to base 2 numbers that is in the binary format.

The binary representation for the number 2 is 0010 and the binary representation for the number 8 is 1000. For 28 the binary value is 0010 1000.

So the value of base 10 for the number (28)10 is (0010 1000)2.

Example 2 for definition of base in math:

Find the base 10 for (1111)2.

Solution:

The given base 2 value is (1111)2.

The binary value for 15 is 1111 using the 8 4 2 1 method.

So the decimal value for the (1111)2 is 15.

Example 3 for definition of base in math:

Convert the base 2 value 11010101 into base 6 of the hexadecimal.

Solution:

The given base 2 value is 11010101.

Separate the binary values as 4 digits.

11010101 = 1101 0101

The hexadecimal values are 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D. . . . . . So,

11010101 = D 5

The hexadecimal value for 11010101 is D5.

Example 4 for definition of base in math:

Convert the base 2 value 10011011 into base 6 of the hexadecimal.

Solution:

The given base 2 value is 10011011.

Separate the binary values as 4 digits.

10011011 = 1001 1011

The hexadecimal values are 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D. . . . . . So,

11010101 = 9 B

The hexadecimal value for 11010101 is 9B.

Understanding Exponential Rules is always challenging for me but thanks to all math help websites to help me out.

Practice problem for definition of base in math:


Convert the (1110)2 into the decimal number.
Answer: 14

Convert 43 into the binary number.
Answer: 01000011

Convert the 10111010 into hexadecimal number.
Answer: B A.

Free Statistics Course Online

Introduction to free statistics course online:

Statistics is done normally with the data collected for specific purposes.  The method used in statistics for finding a representative value of the given data is called as the measure of central tendency. The three measures of central tendency of statistics were Mean, also median and mode. Statistics are all largely used in banking sectors, educationist, industrialist, economist, agriculturalists etc. Free statistics course online is nothing but free course material available on internet for the sake of helping students. Statistics is one of the important topics in mathematics. Let us see free statistics course online.

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Free statistics course online:


Example 1:

Find the mean deviation of the median for the following data: 6,12,7,5,14,12,20,6,8,21,23.

Solution :

Here the total number of observations is 11 which is odd. Arranging the data into ascending order,

5 , 6 , 6 , 7 , 8 , 12 , 12 , 14 , 20 , 21 , 23

Now Median =(11+1/2) or 6th observation = 11

The absolute values of the respective deviations from the median, i.e.,|xi − M| are

6 , 5 , 5 , 4 , 3 , 0 , 0 , 3 , 9 , 10 , 12
Therefore

∑ 11i-1 |xi - M| = 57

M.D.(M) =(1/11) ∑ 11i-1 |xi - M| = (1/11)*57  =5.181.

Example 2:

Find the mean deviation of  the median for the following data: 11,6, 6, 3, 13, 11, 18, 4, 7, 18, 22.
Solution:

Here the total number of observations is 11 which is odd. Arranging the data into

ascending order, we have 3,4,6,6,7,11,11,13,18,18,22

Now Median =(11+1/2) or 6th observation = 11

The absolute values of the respective deviations from the median, i.e.,|xi − M| are

8 , 7 , 5 , 5 ,4, 0 , 0, 2 , 7 , 7 , 11
Therefore
`sum` 11i-1 | - M| = `56`

and  M.D.(M) = `1/11` `sum` 11i-1 |xi - M| =`56/11` =5.6.

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Free statistics course online-examples:


Example 3:

Find the mean deviation of the mean for given data:

6,5,15,9,13,2,7,15

Solution:

Step 1 Mean of the given data are   `barx`


`barx` = `(6+5+15+9+13+2+7+15)/8`   =`72/8` =8

Step 2 The deviations of the respective observations from the mean x, i.e., xi– x are
6– 8,5–8,15–8,9–8,13–8,2–8,7–8,15–8      ( or )   –2,–3,7,1,5,–6,–1,7

Step 3 The absolute values of the deviations, i.e.,|xi − x |are  2,3,7,1,5,6,1,7


Step 4 The required mean deviation about the mean is

M.D. ( `barx` ) = `sum` 8 i-1 |xi-x| / 8

= `(2+3+7+1+5+6+1+7)/8` = `32/8` = 4

Example 4:

Find the mean deviation of the mean for given data :

12, 5, 19, 18, 4, 11, 18, 21, 20, 8, 15, 18, 2, 4, 15, 11, 3, 1, 10, 5

Solution:

find the mean ( `barx` ) of the given data

`barx`   =1/20`sum` 20i-1  xi = `220/20` = 11


The respective absolute values of the deviations from mean, i.e.,|x- `barx` | are

1,6,8,7,7,0,7,10,9,3,4,7,9,3,4,0,8,10,1,6

Therefore
20i-1 |xi - `barx` | = 118

and M.D. ( `barx` ) =`118/20` = 5.9