4th Grade Math Area

Introduction to 4th grade math:

In 4th grade mathematics, we learn about basic numbers, numerals, letters, integers and area of the different shapes. It provides basic idea to the students for solving the simple math problems. Topics under 4th grade mathematics is given below,

Numbers and its operations
Fractions and mixed numbers
Addition and subtraction
Division and multiplication
Geometrical shapes and areas
Algebraic expressions and equations
Logical reasoning
Charts and graphs

Example problems for 4th grade math area


4th grade math problem 1:

Find the area of the square with the side length of 19 cm.

Solution:

Given, side length (a) = 19 cm

Formula:

Area of the square = a2

Substitute the given side length value in the above formula, we get

Area of the square = 192 cm^2

= 361 cm^2

Answer:

Area of the square is 361 cm^2



4th grade math problem 2:

Find the area of the rectangle with the side length of 34 cm and width is 18 cm.

Solution:

Given, side length (l) = 34 cm and width (w) = 18 cm

Formula:

Area of the rectangle = length * width

Substitute the given side length and width values in the above formula, we get

Area of the rectangle = 34 * 18 cm^2

= 612 cm^2

Answer:

Area of the rectangle is 612 cm^2



4th grade math problem 3:

Find the area of the circle with the radius 42 cm.

Solution:

Given, radius of the circle (r) = 42 cm

Formula:

Area of the circle = pr2

Substitute the given side length value in the above formula, we get

Area of the circle = (p * 422) cm^2

= 1764p cm^2

Answer:

Area of the circle is 1764p cm^2

I have recently faced lot of problem while learning Mixed Numbers to Improper Fractions, But thank to online resources of math which helped me to learn myself easily on net.

Practice problems for 4th grade math area


4th grade math problem 1:

Find the area of the square with the side length of 81 cm.

Answer:

Area of the square is 6561cm^2

4th grade math problem 2:

Find the area of the circle with the radius 27.3 cm.

Answer:

Area of the circle is 745.29 cm^2

4th grade math problem 3:

Find the area of the rectangle with the side length of 24.67 cm and width is 29.5 cm.

Answer:

Area of the rectangle is 727.765 cm^2

Variable Solver

Introduction to variable solver:

The variable solver is the mathematical function to solve the equation of the one variable, two variables and also three variables. The variable solver is used to get the values for the given algebraic equation. This variable solver is also used in the electronic circuits to find the voltage across the circuits, current and also the capacity of the circuit.


Examples for variable solver:


Example 1 for variable solver:

Find the value of x for the algebraic equation 5x + 4=94.

Solution:

The given equation is 5x + 4=94.

Subtract 4 on both sides of the algebraic equation.

5x + 4- 4= 94- 4

5x =90

Divide by 5 on both sides of the above algebraic equation

5x/5 = 90/5

x= 18

The value of x for the algebraic equation 5x + 4=94 is 18.

Example 2 for variable solver:

Find the value of x and y for the algebraic equations    2x+ 3y =4 and 2x- 3y =4.

Solution:

The given algebraic equations are 2x+ 3y =4 and             2x- 3y =4.

Add the two equations to get first the value of x.

2x+ 3y =4

2x- 3y = 4

______________

4x = 8

Divide 4 on both sides of the above equation.

4x/ 4 = 8/ 4

x= 2

To get the value of y substitute the value of x in the given equation. Take any one of the given equation to get the value of y.

Substitute the value of x in this algebraic equation    2x+ 3y =4.

2 (2) + 3y=4

4+ 3y =4

Subtract 4 from the above equation.

4-4 + 3y = 4-4

3y= 0

Divide 3 on both sides of the above quadratic equation to get the value of y.

3y/3 = 0/3

y= 0

The values of x and y for the given algebraic equations are x=2 and y=0.

Exercise problem for variable solver:


Find the value of x for the algebraic equation 2x+ 3=13.
Justification: x=5.

Find the values of x and y for the algebraic equations 4x- 2y =14 and 2x + 2y =10
Justification: x=4 and y= 1.

Equation as Relations Solver

Introduction to equation as relations solver:

In this article equation as relations solver, we will solve the equation which is formed by some relation. Let us see how to make the equation with given statement and how to solve the equation. Generally the algebraic equation constitutes  of variables and expressions and we have to solve the equation to find the solution. Let us solve some example problems for equation as relations solver.


Example problems for equation as relations solver:


Example problem 1 - Equation as relations solver

A number is eight more than another, sum of the smallest integer and five times the greatest is 70.What is the greatest integer?

Solution:

Consider Smallest number x

Greatest number x+8

x+5(x+8) =70

x+5x+40=70

6x=30

x=5

Smallest number x=5

Greatest number x+8=13

Example problem 2 - Equation as relations solver

The perimeter of a rectangle is given by 58 m and the length is nine more than three times the breadth find out the breadth?

Given:

Perimeter=58 m

l=3b+9

Solution:

Perimeter of a rectangle=2(l+b)

2(3b+9+b)=58

2(4b+9)=58

8b+18 = 58

8b=40

b=5 m

Example problem 3 - Equation as relations solver


The price of one pencil and note book is $15 then what is the price of 5 pencil and 5 note book?

Solution:

Consider pencil as x

Note book as y

So from the given statement x+y=15-------1

The price of 5 pencil and 5 note book=5x+5y=?

We can write the above equation as

The price of 5 pencil and 5 note book =5(x+y)

From the first equation we can substitute the x+y value

The price of 5 pencil and 5 note book =5(x+y)

=5(15)=75

The price of 5 pencil and 5 note book =$75

Example problem 4 - Equation as relations solver

The ages of John and Krithick differ by 12 years when comparing. If 3 years ago, the elder one be 5 times as old as the younger boy, find their present ages.

Solution:

Consider the age of the John be x years.
The age of the Krithick = (x + 12) years.
:. 5 (x - 3) = (x + 12 - 3)

5x-15=x+12-3

4x=15+12-3

4x=27-3

4x=24

x=6

John present age is 6 years

Krithick present age is 18 years

Easy Algebra Solver

Introduction to easy algebra solver:

Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorial, and number theory, algebra is one of the main branches of pure mathematics.

Source: From Wikipedia.

Please express your views of this topic College Algebra Solver by commenting on blog.

Example problems for easy algebra solver:


Some example problems are solved with solution for easy algebra solver.

Example 1:

Determine the x intercept of the equation.

4x - 7y = 12

Solution:

Given the equation

4x - 7y = 12

To find the x intercept we set y = 0 and solve for x.

4x - 0 = 12

Solve for x.

x = 12 / 4

x = 3

The x intercept is at the point (3, 0).

Example 2:

Evaluate f (3) - f (2)

f(x) = 6x + 3

Solution:

Given the function

f(x) = 6x + 3

f (3) - f (2) is given by.

f(3) = (6(3) + 3) = 18 + 3 = 21

f(2) = (6(2) + 3) = 12 + 3 = 15

f (3) - f(2) = (21) - (15) = 6

Solution to the given function is f(3) - f(2) = 6

Example 3:

Find the slope of the line or gradient passing through the points

(-5, -5) and (7, 7).

Solution:

Given the points (-5, -5) and (7, 7), the slope m is given by

m = (y2 - y1) / (x2 - x1)

= (7 – (-5)) / (7 – (-5))

= 12 / 12

= 1

m = 1

Solution to the given slope of the line m = 1.

Example 4:

Find the slope of the line

12x - 8y = 18

Solution:

Given slope of the line

12x - 8y = 18

Write the above equation in the form of slope intercept y = mx + b and identify the value of m the slope.

-8y = -12x + 18        both side can be divided by -8

-8y/-8 = -12x/-8 + 18/-8

y = 3/4x - 9/4

The slope is given by the coefficient of x which is 3/ 4.

Slope = 3/ 4

Example 5:

Solve x for the following linear equation 7x - 3 = 144
Solution:
Add by 3 on both sides, we get
7x - 3 + 3 = 144 + 3
Simplify both sides:
7x = 147
Divided by both sides on 7:
7x/7 = 147/7
Simplify both sides:

x = 21.

Solution to the linear equation is x = 21.

Easy algebra solver practice problems:


Practice problems for easy algebra solver are given below.

1) Determine the x intercept of the equation.

8x - 12y = 24

Answer: The x intercept is at the point (3, 0)

2) Evaluate f (4) - f (3)

f(x) = 8x + 7

Answer: f(4) – f(3) = 8

3) Find the slope of the line or gradient passing through the points

(-6, -8) and (10, 12).

Answer: m = 4/ 5

4) Find the slope of the line

15x - 4y = 25

Answer: slope = 15/4

5). Solve x for the following linear equation 8x – 9 = 87

Answer: Solution to the linear equation is x = 12

Problem Solving Unit

Problem solving unit:

A unit of measurement is a definite magnitude of a physical quantity, defined and adopted by convention and/or by law, that is used as a standard for measurement of the same physical quantity. Any other value of the physical quantity can be expressed as a simple multiple of the unit of measurement.

For example, length is a physical quantity. The meter is a unit of length that represents a definite predetermined length. When we say 10 meters (or 10 m), we actually mean 10 times the definite predetermined length called "meter". (Source-Wikipedia)

I like to share this Significant Figures Calculator with you all through my article.

Problem solving unit-Example 1:


Convert 748.6 cm into meter.

Solution:

Here the conversion is from centimeter to meter. i.e. from lower unit to higher unit.

100cm = 1m.

Hence 748.6cm = (748.6/100) m

= 7.486 m (shifting the decimal two digits to the left)

The solution is 7.486 m.

Problem solving unit-Example 2:

Convert 50.1735 km into meter.

Solution:

Here the conversion is from higher to lower. Hence we have to shift the decimal point to the right.

1km = 1000 m

50.1735 km = 50.1735 × 1000 m

= 50173.5 m

The solution is 50173.5m

Problem solving unit-Example 3:

Convert 6m into millimeter.

Solution:

Note: Here we are converting the unit meter into millimeter. i.e. from higher unit to lower unit. So the operation should be multiplication.

1 m = 1000 mm

Hence 81 m = 81 × 1000 mm

= 81000 mm

The solution is 81000 mm

Problem solving unit-Example 4:


Express 8 kg 3 dag in grams

Solution:

1 kg = 1000 g

1 dag = 10 g

Hence 6 kg 5 dag = 6 × 1000 g + 5 × 10 g

= 6000 g + 50 g

= 6050 g

The solution is 6050g

Problem solving unit-Example 5:

Express 2769 g in kilograms.

Solution:

1000 g = 1 kg

Hence 3766 g = (3766/1000) kg

= 3.766 kg

The solution is 3.766 kg

Problem solving unit-Example 6:

Express 7402 kg into quintals.

Solution:

100 kg =1q

8402 kg =8402/100 q

= 84.02 q

The solution is 84.02 q

Problem solving unit-Example 7:

Convert 10.1835 km into meter.

Solution:

Here the conversion is from higher to lower. Hence we have to shift the decimal point to the right.

1km = 1000 m

10.1835 km = 10.1835 × 1000 m

= 10183.5 m

The solution is 10183.5 m

Free Online Tutors

Introduction to free online tutors:

Online tutors are those tutors who can teach from the distance part through computer and internet.  Online tutors can be in any part of the world and the student can also be any part of the world.  They both interact through an interface.  Computer and internet is the prime requirement of the online tutoring.

Online tutors are able to each form grade I or even kindergarden students using voice transfer technology.

Free online tutors-tutorvista as online tutoring company

Tutorvista is one of the important online tutoring company which provides quality services to all the parts of the world catering to the need of variety of need.  Tutorvista is primary based in Bangalore in India.  But it hires tutors all over the globe. It is established 5 years back and is one of the prime operator in the online tutoring.  Tutorvista has proved how successful the online tutoring and how useful it can be.  It makes a difference in the grade  which students gets.  Tutorvista primarily deals with science, Math and English for all grade of students.

It Now focus on the US student, but it had catered to the needs of the Korean, British and Australian students also.

Having problem with Simplifying Rational Expressions keep reading my upcoming posts, i will try to help you.

free online tutors-tutorvista-online tutoring company


Tutorvista uses one of the sophisticated technology for tutoring in the world.  Students can log in at any time and can get access to tutor immediately.  Tutorvista has a tutor base of more than 2000 and is expanding.  The number of students who had benefited from the company is enormous.

Tutorvista uses the white board which can be seen by both the student and tutor and on which both can write.  Which is visible in both the side.  It is a personalised one to one teaching with voice also available.  The session are normally of 45 minutes duration and the session can be replayed to clarify the doubt.

There are chat box also which can be used for chatting is very power ful tool.  Files can be shared in the board and can be seen in both the ends.

Tutorvista gives free online demo session which can be used by the students to get a first hand experience of the site and the method of teaching

Find Percentage Difference

Introduction to find percentage difference:

Percentage is expressing any number in a fraction with the denominator as 100. The symbol used for the percentage is ‘%’. Percentage difference is defined as the comparing a previous value to the new value.

Formula for percentage difference = [Previous value – new value] / 100

I like to share this homework help algebra 2 with you all through my article.

Word problem on find percentage difference:


David lived in a United States of America. When David left the country the population was 920 million. David recently heard that the population has decreased by 6%. What is the present population?

Solution:

Find out the decrease percentage 920*6/100 = 5520/100 = 55.2 million

Then the new population is old population minus the decreased population

920-55.2 = 864.8 million

The population is now 864.8 million



Word problem 2:

Shan diets and decrease his weight 67kg to 65kg. Find the percentage decrease?

Solution:

Initially find the weight loss = 67-65 = 2kg

This 2kg is decrease the original weight. So the percentage will modify the original,

Let us take x as the decrease percentage

2=x * 67

Divide by 67 on both sides to make the variable alone

2/67 = 67x/67

0.0298 = x

Convert the decimal to percentage we get,

X=2.98%

The loss of weight in percentage is 2.98%

Understanding Sequence and Series is always challenging for me but thanks to all math help websites to help me out.

Word problem on find percentage difference


If 58 students in a class are boys and 42 students are in girls. Find the percentage difference between boys and girls?

Solution:

First find out the total number of students in a class

Boys + girls = 58+42 = 100

After that find out the percentage of boys in a class

Boys percentage = total number of boys / total number of students

= 58/100 = 58 %

After that find out the percentage of girls in a class

Girls percentage = total number of girls / total number of students

= 42/100 =42 %

Percentage difference = 58-42 =16

The girls are 16 % percentage lesser than boys